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-9k^2=1+6k
We move all terms to the left:
-9k^2-(1+6k)=0
We add all the numbers together, and all the variables
-9k^2-(6k+1)=0
We get rid of parentheses
-9k^2-6k-1=0
a = -9; b = -6; c = -1;
Δ = b2-4ac
Δ = -62-4·(-9)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$k=\frac{-b}{2a}=\frac{6}{-18}=-1/3$
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